Question

in the given figure if AC=BD prove AB=CD.

Answer 1

From the given figure,
                           AC  = AB + BC
                            BD  =  BC + CD
It is given that AC = BD.
Putting the values of AC and BD, we get:
                               AB + BC =  BC + CD..................(1)
According to Euclid's axiom, when equals are subtracted from equals, the remainders are also equal.
Subtracting BC from both sides in equation (1), we get:
                            AB + BC − BC = BC + CD − BC
                           AB = CD
Hence, proved.                                

Answer 2

figure to bata yarr.....