In the given figure, if AC is bisector of angle BAD, such that AD=AB=3cm and AC 5cm, show that triangle ABC = triangle ADC and BC = CD?
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from the RHS congruence
R=Right angle
i.e, angle CBA = CDA
H= hypotheneus
i.e, BA =DA
S= side
i.e,CA = CA
common side
we can find out lenght of the side
CB and CD
by pythagoras triplets
3,4,5 are pythagoras triplet
the lenght these sides of triangle froms a right angle triangle
SO THOSE TRIANGLES ARE CONGRUENT
WE CAN SAY THAT CB = CD
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