Question

In the given figure, if AC is bisector of _BAD such that AD = 3 cm, AB= 3 cm and AC = 5 cm, then the value of CD + BC is​

Answer 1

Answer:

4 cm correct✅ answer

Step-by-step explanation:

In

ΔABCandΔADC,

AC=AC(Common)

∠B=∠D(Each90∘)

<BAC=<DAC

(∵AC is the bisector of ∠A)

∴

ΔABC≅ΔADC(AAS axiom)

∴

BC=CD

and

AB=AD

(c.p. c.t.)

Now in right

ΔABC,

AC2=AB2+BC2

⇒

(5)2=(3)2+BC2

⇒

25=9+BC2

⇒

BC2=25−9=16=(4)2

∴ BC=4cm

But

CD=BC

∴ CD=4cm