Question

In the given figure, if AD 1 BC, AC=4, BD=2, AB=a, and CD=b then a²+b²=​

Answer 1

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{purple}{SoLUTioN :-}}}}$

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$\mathtt{By\:Pythagorean\:Theorm}$

a² → 2² + AD²

a² → AD² + 4 --------------- { 1 }

$\mathtt{Similarly,}$

b² → 4² - AD²

b² → 16 - AD² -------------- { 2 }

$\mathtt{By\:adding\:( 1 )\:and\:( 2 )\:.}$

a² + b² → AD² + 4 + 16 - AD²

a² + b² → 20 .

Here is the answer .