In the given figure if ∆ AED~∆ ABC,then DE is equal to a)5.5cm b)6.5cm c)7.5cm d)5.6cm
Answers
Answer:
5.6cm
Step-by-step explanaton Given, AE=12 cm AB=16+14=30cm AC=14cm Therefore DE=AE×AC/AB So,that DE= 12×14/30 . DE=168/30 . DE=5.6cm . Hence proved"
DE = 5.6 cm if ∆ AED~∆ ABC
Given:
- ΔADE ~ ΔABC
- From the figure: ( Attached , Missing in the question)
- AE = 7.2 cm
- BE = 4.2 cm
- AD = 7.6 cm
- BC = 8.4 cm
To Find:
- DE
Solution:
- Corresponding sides of similar triangles are in proportion
Step 1:
Equate ratio of corresponding sides of ΔADE ~ ΔABC
AD/AB = AE/AC = DE/BC
Step 2:
Using segment addition postulate find AB
AB = AE + BE = 7.2 + 4.2 = 11.4 cm
Step 3:
Use AD/AB = DE/BC from step 1 and substitute the values and solve for DE
7.6/11.4 =DE/8.4
=> 2/3 = DE/8.4
=> 2 = DE/2.8
=> DE = 2 * 2.8
=> DE = 5.6 cm
Correct option is d) 5.6 cm
(Although your Question missing figure , but same has been attached)