in the given figure if angle A = angle B And DE // AB prove that AD = BE
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Step-by-step explanation:
angle A =angleB ( given)
so there sides also equal by isoscale triangle rule
so AC=BC
AB||DE (given)
construct a line AF which bisect DE and AB the middle point is G
In triangle CGD&CGE
ANGLE D = angle E
CG=CG
DG=EG
so, ∆CGD =~ ∆CGE
so, CD=CE
BY THIS AD=BE
hence proved
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