Question

In the given figure, if angle ABD=106° and angle ACF = 118. Then value of angle A is A a) 44° b) 54° 1069 118° c) 34° kel DB CF d) 36°​

Answer 1

Step-by-step explanation:

Simply,

angle ABC = 180 -106 = 74

and angle ACB = 180 - 118 = 62

Now angle A + 74 + 62 = 180

and angle A = 44

Answer 2

Step-by-step explanation:

Given:

∠$ABD=106^{o}$

∠$ACF=118^{o}$

To find: ∠$A$

Calculation:

From linear pair angles:

∠$ABD+$∠$ABC=180^{o}$

∠$ABC=180-106=74^{o}$ and

∠$ACF+$∠$ACB=180^{o}$

∠$ACB=180-118=62^{o}$

Now, in Δ$ABC$, sum of all angles are $180^{o}$:

∠$A+$∠$ABC+$∠$BCA=180^{o}$

∠$A=180-(62+74)=44^{o}$

So, angle $A=44^{o}$

Answer:

∠$A=44^{o}$