Question

in the given figure,if angle ABD is 25° and angle BDC is 55° then prove that angle ADB+ angle CBD=100°​

Answer 1

Answer:

In cyclic Quadilateral we know that sum of opposite sides is 180 degrees so

angle ADB + angle bdc + angle CBD + angle ABD = 180°

it is given that angle abc + angle bdc is equal to 80 degrees

then angle ADB + angle CBD is equal to 100°

Answer 2

Answer:

Step-by-step explanation:

We know that the sum of the opposite angles of a

con-cyclic quadrilateral = 180°

Therefore,∠ABC + ∠ADC = 180°

⇒∠ABD + ∠CBD + ∠ADB + ∠BDC = 180°

⇒∠CBD + ∠ADB + 25° + 55° = 180°

⇒∠CBD + ∠ADB + 80° = 180°

⇒∠CBD + ∠ADB = 180° - 80° = 100°

Hence, Proved.

Hope it helps!!