Question

in the given figure if angle AOC=50° then (angleAOD+angleCOB) os equal to​

Answer 1

In the given figure, if ∠AOC = 50°, then find (∠AOD + ∠COB). Now, ∠AOD = ∠COB [Vertically opp. angles] ∴ ∠AOD + ∠COB = 130° + 130° = 260°.

Answer 2

Answer:

AOC=50

AngAOC= Ang DOB=50 ( vertically opp angles)

Ang COB+ Ang AOD +AngAOC +Ang DOB= 360

then and COB +ang AOD= 360-50 -50

HENCE   COB+AOD=260

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