in the given figure if Angle B A D = 60 degree and angle ADC = 105 degree then determine angle DPC
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Hi.
Here is your answer---
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Given---
∠ ADC = 105°
We know,
∠ADC + ∠ABC = 180° [Opposite angles of the Cyclic Quadrilateral are Supplementary]
∠ABC ( or ∠PBA) = 180° - 105°
= 75°
∠DAB( or ∠PAB) = 60° [Given]
Using the Angle Sum Property in ΔPAB,
∠PAB + ∠PBA + ∠APB = 180°
60° + 75° + ∠APB = 180°
∠APB = 180° - 135°
∠APB = 45°
Thus, ∠DPC(or ∠APB) is 45°.
_______________________
Hope it helps.
Have a nice day.
Here is your answer---
___________________
Given---
∠ ADC = 105°
We know,
∠ADC + ∠ABC = 180° [Opposite angles of the Cyclic Quadrilateral are Supplementary]
∠ABC ( or ∠PBA) = 180° - 105°
= 75°
∠DAB( or ∠PAB) = 60° [Given]
Using the Angle Sum Property in ΔPAB,
∠PAB + ∠PBA + ∠APB = 180°
60° + 75° + ∠APB = 180°
∠APB = 180° - 135°
∠APB = 45°
Thus, ∠DPC(or ∠APB) is 45°.
_______________________
Hope it helps.
Have a nice day.
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please learn it and answre
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