Question

In the given figure, if angle CDE = angle DEC then angle AED = ?​

Answer 1

Answer:

124°

Step-by-step explanation:

In ∆ ABC

angle A +angle B+ angle C= 180°

{Angle Sum Property}

20+48+angle C=180

68+angle C=180

angle C=112

In∆ CED

angle CDE+angle DEC =angle ACB

{Exterior Angle Property}

2angle CED =112

{angle CED =angle DEC}

angle CED =56

Now,

angle CED+angle AED=180

{linear pair}

56+angle AED = 180

angle AED=180-56

=124

Answer 2

Answer:

124

Step-by-step explanation:

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