In the given figure , if aob is a diameter of a circle , with centre o angle ebd =15 degrees and acd=120 degrees.Find the measure of abe.
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Step-by-step explanation:
Given-
O is the centre of a circle of which AOB is a diameter.
CD is another chord, intersecting AOBˉ.
∠BOD=120o
To find out- ∠ACD=?
Solution-
∠AOD=180o−∠BOD=180o−120o=60o ....(linear pair).
Now ∠AOD is the angle subtended by the minor arcAD to the centre and ∠ACD is the angle subtended by the minor arc AD to the circumference at C.
∴∠ACD=21∠ACD=21×60o=30
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