Question

In the given figure if AOB is a line then find the measure of angle BOC angle COD and angle DOC.

Answer 1

5y + 3y + 2y = 180°
10y = 180 °
$y = 180 \div 10$
$y = 18 \: \: \: then \: the \: value \: of \: y \: is \: 18$
$5y = 18 \times 5 = 90$
$3y = 3 \times 18 = 54$
$2y = 2 \times 18 = 36$
COD = 54°
BOC = 36°

AND
COD =DOC

Answer 2

Given,

AOB is a line

To find,

Measurements of angle (i) AOD (ii) DOC (iii) COB

Solution,

We are given that AOB is a line.

The angles placed on a line sum up to 180°

So,

∠AOD + ∠DOC + ∠COB = 180°

Which means that

5y + 3y + 2y = 180°

10y = 180°

y = 18°

So,

(i)∠AOD = 5y

= 5 x 18

= 90°

(ii)∠DOC = 3y

= 18 x 3

= 54°

(iii)∠COB = 2y

= 2 x 18

= 36°

Thus, the Measurements of angle (i) AOD is 90° (ii) DOC is 54° (iii) COB is 36°