Question

In the given figure. If AOB is a line, then the value of x is
A=30
B=45
C=50
D=70​

Answer 1

Answer:

C option is correct

Step-by-step explanation:

Angle (x + 10)° + Angle (x)° + Angle (x + 20)° = 180°

(Since AOB is a straight line angle is 180°)

therefore,

(x+10) + x + (x+20) = 180

3x + 30 = 180

3x = 150

x = 150/3

x = 50

Answer 2

GIVEN:-

• AOB is a line

• $\rm{\angle{COA = x+10},\angle{COD = x}\:and\: \angle{DOB = x+20}}$

TO FIND :-

• The Value of x.

CONCEPT USED:-

• The Sum of the angle in a line is 180°.

Now,

$\implies\rm{\angle{COA} + \angle{COD} +\angle{DOB} = 180^{\circ}}$

$\implies\rm{x+10^{\circ} +x + x+20^{\circ} = 180^{\circ}}$

$\implies\rm{ 3x + 30 = 180^{\circ}}$

$\implies\rm{ 3x = 150^{\circ}}$

$\implies\rm{ x = \dfrac{150}{3}}$

$\implies\rm{ x = 50^{\circ}}$.

Therefore,

$\rm{\angle{COA = x+10 = 60^{\circ}}}$

$\rm{\angle{COD = x = 50^{\circ}}}$

$\rm{\angle{DOB = x + 20 = 70^{\circ}}}$

MORE TO KNOW :-

• Sum of two Co-interior angle is 180°

• When two lines Intersect each other then Vertically Opposite angles are equal.

• When the angles of two different lines are corresponding then the lines are Parallel

• When the angles of two different lines are Alternate then the lines are Parallel