Question

in the given figure, if AOB is a line thrn measure of angle BOC,angleCOD and angle DOA respectively are​

Answer 1

Answer:

5y + 3y + 2y = 180°

10y = 180 °

y = 180 \div 10y=180÷10

y = 18 \: \: \: then \: the \: value \: of \: y \: is \: 18y=18thenthevalueofyis18

5y = 18 \times 5 = 905y=18×5=90

3y = 3 \times 18 = 543y=3×18=54

2y = 2 \times 18 = 362y=2×18=36

COD = 54°

BOC = 36°

AND

COD =DOC