Question

in the given figure, if AOB is a straight line then find the value of angle AOC , angle BOD and angle BOC​

Answer 1

Answer:

angle AOC + angle COD + angle DOB = 180

as AOB is a straight line then ,

y+20+2y+30+y+10= 180°

4y + 60 =180

4y =180 - 60

4y = 120

y = 30°

so angle AOB =30+20=50°

angle COD= 60+30 = 90°

and

angle DOB =30+10=40°

Answer 2

Answer:

y+ 20+2y+30+y+10=180

4y+60=180

4y=120

y=30

<COD=2y+30=90

<AOC=y+20=50

<DOB=40