Question

in the given figure,if AOC+BOC+BOD=338degree, find all
the four angles​

Answer 1

Heyaaa...

As the sum of all angles around a point is 360 degree

AOC+BOC+BOD+AOD=360

338+AOD=360

AOD=360-338

AOD=22

As V.O.A. are equal so AOD=BOC=22

AOD+BOD=180 (linear pair)

22+BOD=180

BOD=180-22

BOD=158

By V.O.A.

BOD=AOC=158

Hope this helps...!!!

Answer 2

AOC = DOB. [vertically opposite]

AOC+BOC+BOD=338°

AOC+BOC+AOC=338°

2AOC+BOC = 338°................ (i)

AOC+BOC. = 180° [ linear pair ]

AOC. = 180° - BOC ...........(ii)

on putting the value (ii) in (i) we get.

2(180°-BOC) + BOC. = 338°

360°-2BOC + BOC =338

-BOC. = 338°-360°

-BOC. = -22°

BOC. = 22 = AOD

AOC. =180° - BOC

= 180° -22

AOC. = 158° =BOD.

Hey mate hope it's helpful to you.

Thanks