Question

In the given figure if AP= 2 cm , BQ =3 cm and RC= 4 cm, then calculate the perimeter of ∆ ABC.
(Class 10 Maths Sample Question Paper)

Answer 1

FIGURE IS IN THE ATTACHMENT.
Given:

AP = 2 cm
BQ = 3 cm
RC = 4 cm
AP = AR =  2 cm
BQ =  BP =3 cm
RC = CQ = 4 cm

(We know that two tangents drawn from an external point to the circle are equal in length.)
AB = AP + BP = 2 + 3 = 5 cm
BC = BQ + CQ = 3 + 4= 7 cm
CA = CR + AR = 4 +2 = 6 cm
Perimeter of ∆ ABC = AB + BC + CA
Perimeter of ∆ ABC = 5 + 7 + 6 = 18 cm.

Hence, the Perimeter of ∆ ABC = 18 cm.
HOPE THIS WILL HELP YOU...

Answer 2

Answer:

4cm

Step-by-step explanation:

We have two chords AB and CD intersect at P ,

AP = 2 cm , BP = 6 cm , CP = 3 cm

We know " Theorem : When two chords intersect each other inside or outside of the circle , The rectangle formed by two segment of one chord is equal in Area of rectangle formed by two segment of other chord . "

So , we get

AP × BP = CP × DP

So, substitute all values , we get

2 × 6 = 3 × DP

3 DP = 12

DP = 4

Hope it helps

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