Question

in the given figure if AP ⊥ QR and PS = PQ then ∠AQR is always greater than

Answer 1

Answer:

angle QAP is the correct answer

Step-by-step explanation:

in triangle AQP,

angle QAP+ angle AQP+ 90⁰ = 180⁰

So, angle QAP + angle AQP = 90⁰

AQ> QP

So, angle AQP > angle QAP...

Answer 2

Heyy mate.....

Your answer is last option Angle ARQ

Are you BTS Army???

You can answer this in any of my question...