In the given figure, if area of parallelogram ABCD is 29 cm square and AB=5.8, then find the height of parallelogram ABEF
Attachments:
Answers
Answered by
12
you can easily understand by the given figure.
Answer is 5cm.
hope this will help you.
mark this answer as brainiest plz.
Answer is 5cm.
hope this will help you.
mark this answer as brainiest plz.
Attachments:
Answered by
12
as per theory that "if two parallelogram has a same base then the area of both the parallelogram will be same".
And here the parallelogram ABCD and ABEF has same base AB
Therefore,
Area of ABCD = Area of ABEF
As given that Area of ABCD=29 cm^2
So Area of ABEF = 29 cm^2
Now,
Area of parallelogram ABEF = base*height
here, base=AB=5.8cm
29 = 5.8 * height
height = 29/5.8
height = 5 cm
Answer:- Height = 5 cm
And here the parallelogram ABCD and ABEF has same base AB
Therefore,
Area of ABCD = Area of ABEF
As given that Area of ABCD=29 cm^2
So Area of ABEF = 29 cm^2
Now,
Area of parallelogram ABEF = base*height
here, base=AB=5.8cm
29 = 5.8 * height
height = 29/5.8
height = 5 cm
Answer:- Height = 5 cm
Similar questions