Question

In the given figure, if

 =   =  BEC 120 DCE 25 , ,

then find

BAC​

Answer 1

1:∠BAC = ∠CDE (Angles in the segment of the circle)

In ΔCDE,

∠CEB = ∠CDE + ∠DCE (Exterior angles of the triangle)

⇒ 120° = ∠CDE + 25°

⇒ ∠CDE = 95°

Thus, ∠BAC = 95°

2:

∠BEC is exterior angle of △CDE

∴∠CDE + ∠DCE = ∠BEC

⇒∠CDE + 25° = 120°

⇒ ∠CDE = 95°

Answer 2

Answer:

∠BAC=95°

Step-by-step explanation:

Your answer is in the picture

Hope it is clear...

Please mark it as the brainliest

PLEASE