Question

in the given figure if block starting from rest on a smooth surface reaches the point b then magnitude of velocity of block at b is

Answer 1

WE CAN DO THIS BY CONSERVATION OF ENERGY ..
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CHANGE IN POTENTIAL ENERGY =
CHAGE IN KINETIC ENERGY

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INITIAL POTENTIAL ENERGY = M×G×H
= 2 ×10×5
=. 100
FINAL POTENTIAL ENERGY = 0
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INITIAL KINETIC ENERGY = 0

FINAL KINETIC ENERGY = 1/2 × m × v^2
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VELOCITY FINAL = 10

ANSWER - 10
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Answer 2

Answer:

(1) 10 m/s

Explanation:

Mass of object (m) = 2 kg

Height (h) = 5m

Acceleration due to Gravity (g) = 10m/s²

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i) Potential Energy = mhg

ii) Kinetic Energy = 1/2 mv²

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Total Potential Energy = Total Kinetic Energy

mhg = 1/2 mv²

2 x 5 x 10 = $\frac{1}{2}$ x 2 x v²

v² = $\frac{2*2*5*10}{2}$

v² = 2 x 5 x 10

v² = 100

v = √100

v = 10 m/s

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