Question

in the given figure if coefficient of friction between block and surface is 0.1 then find acceleration produced by the resultant force acting on the block (take g=10m/s2

Answer 1

First of all we have to calculate frictional force by using below equation,

F =μR

$F = 0.1 * mg$

$F = 0.1*5*10$

$F = 5N$

$Frictional Force = 5N$

But we know that frictional force is acting on opposite direction of the motion.

Therefore,

net force = 15N -5N = 10N

Now we can use Newton's second law,

$F = ma$

$10 = 5 *a$

$a = 2 m/s^{2}$

Answer 2

Answer:

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Explanation:

i also had the exact same doubt, all the best for tomorrow's exam