In the given figure, if D is the mid-point of the hypotenuse AC of right AABC, then BD is equal to (1) 5 cm (3) 2 cm (2) 2.5 cm (4) 3 cm
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Area of triangle ABD = Area of trinagle BCD
⟹21DB.DA=21DB.DC [Area of triangle =21×b×h]
⟹DA=DC
∵ Circumradius R=4△AB×BC×AC
=4×21×AB×BCAB×BC×AC
⟹BD=R=2AC [∵Circumradius (R)=BD]
[/tex]
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