in the given figure if D is the midpoint of BC find the value of tan x°/ tan y°
Attachments:

Answers
Answered by
51
Hope it will help u
... If any questions ..or dought u can ask .. me .. I will try to help u ....
Name Harshit
Attachments:

Sumit2099:
can you do it in a more defined way please........?
Answered by
41
tan x= side opposite to x/ side adjacent to x
tan x=AB/BD
tan y = side opposite to y / side adjacent to y
tan y= AB/BC
tan x/tan y= (AB/BD)/(AB/BC)
AB in numerator cancels AB in denominator so we are left with BC and BD.
ans = BC/ BD.
tan x=AB/BD
tan y = side opposite to y / side adjacent to y
tan y= AB/BC
tan x/tan y= (AB/BD)/(AB/BC)
AB in numerator cancels AB in denominator so we are left with BC and BD.
ans = BC/ BD.
Similar questions