Question

in the given figure, if D is the midpoint of the hypotenuse AC of the hypotenuse AC of right triangle ABC, Then BD is equal

1) 5cm
2)2.5cm
3)2cm
4)3cm

urgent guys please answer fast
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Answer 1

Answer:

2.5

Step-by-step explanation:

First find the length of hypotenuse side using Pythagoras theorem the divide it by two

${a}^{2} + {b}^{2} = {c}^{2}$

${4}^{2} + {3}^{2} = {c}^{2}$

${4}^{2} + {3}^{2} = 25$

$\sqrt{25} = 5$

$5 \div 2 = 2.5$

Answer 2

Answer:

2.5

First find the length of hypotenuse side using Pythagoras theorem the divide it by two

{a}^{2} + {b}^{2} = {c}^{2}a

2

+b

2

=c

2

{4}^{2} + {3}^{2} = {c}^{2}4

2

+3

2

=c

2

{4}^{2} + {3}^{2} = 254

2

+3

2

=25

\sqrt{25} = 5

25

=5

5 \div 2 = 2.55÷2=2.5