Question

In the given figure, if DE || BC, AE = 8 cm, EC = 2 cm and BC = 6 cm, then find DE.
(PIC REFERS ATTACHMENT)
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Answer 1

Answer:

As DE II BC, and angle A is common,

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cm

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cmAs the both triangles are similar,

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cmAs the both triangles are similar,Ratios of their respective sides are equal.

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cmAs the both triangles are similar,Ratios of their respective sides are equal.AE/ AC= DE/ BC

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cmAs the both triangles are similar,Ratios of their respective sides are equal.AE/ AC= DE/ BC8/10 DE/6

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cmAs the both triangles are similar,Ratios of their respective sides are equal.AE/ AC= DE/ BC8/10 DE/6DE = 48/10 = 4.8 cm

As DE II BC, and angle A is common,triangle ADE ^ triangle ABC.AE 8 cm, EC = 2 cm, AC =8 +2 10 cmAs the both triangles are similar,Ratios of their respective sides are equal.AE/ AC= DE/ BC8/10 DE/6DE = 48/10 = 4.8 cmDE 4.8 cm

Answer 2

Vanakam _/\_

Answer:-

As DE || BC, and angle A is common, triangle ADE ~ triangle ABC. AE = 8 cm, EC = 2 cm, AC = 8 + 2 = 10 cm. As the both triangles are similar, Ratios of their respective sides are equal. AE / AC = DE / BC 8 / 10 = DE / 6

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