In the given figure,if DE||BC,AE=8CM,EC=2CM AND BC=6CM,THEN FIND THE DE
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As DE || BC, and angle A is common,
triangle ADE ~ triangle ABC.
AE = 8 cm, EC = 2 cm, AC = 8 + 2 = 10 cm
As the both triangles are similar,
Ratios of their respective sides are equal.
AE / AC = DE / BC
8 / 10 = DE / 6
DE = 48 / 10 = 4.8 cm
DE = 4.8 cm
If it helped you, please mark the answer as the Brainliest. Please!
triangle ADE ~ triangle ABC.
AE = 8 cm, EC = 2 cm, AC = 8 + 2 = 10 cm
As the both triangles are similar,
Ratios of their respective sides are equal.
AE / AC = DE / BC
8 / 10 = DE / 6
DE = 48 / 10 = 4.8 cm
DE = 4.8 cm
If it helped you, please mark the answer as the Brainliest. Please!
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