Question

(In the given figure, if □ KLMN is a parallelogram then A(∆KLM) : A(∆LNM) = ​

Answer 1

Answer:

∠KLM=45

Step-by-step explanation:

⇒ In given figure KLMN is a parallelogram.

⇒ Let in figure PL⊥KO

⇒ So, ∠PLK=90

∘

⇒ Let LM is angle bisector of ∠PLK such that,

⇒ ∠MLP=∠KLM --- ( 1 )

⇒ Since, ∠PLK=90

∘

⇒ ∠MLP+∠KLM=90

∘

⇒ 2∠KLM=90

∘

∴ ∠KLM=45

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I hope this help ful

Answer 2

Hope u find it helpful.