Question

in the given figure if line segments PQ and RS intersect at point T such that angle PRT=40°, angle RPT=95° and angle TSQ=75°, find angle SQT​

Answer 1

Solution:-

• ∠PTR=180°-(95°+40°)----(Angle Sum property of a triangle.)

∠PTR=180°- 135°

∠PTR=45°

• ∠STQ=∠PTR=45°---(vertically opposite angle.)

∠SQT = 180°-(45°+75°)----(Angle Sum property of a triangle.)

∠SQT = 180°-120°

∠∠SQT = 60°(Answer)

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