In the given figure, if lines PQ and RS intersect at point T, such that ∠PRT = 40º, ∠RPT = 95º and ∠TSQ = 75º, find ∠SQT.
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Given:
- PQ and RS intersect at point T.
- ∠PRT = 40°, ∠RPT = 90° and ∠TSQ = 75°.
To Find:
- ∠SQT
Solution:
Using angle sum property for ΔPRT, we obtain
→ ∠PRT + ∠RPT + ∠PTR = 180º
→ 40º + 95º + ∠PTR = 180º
→ ∠PTR = 180º − 135º
→ ∠PTR = 45º
→ ∠STQ = ∠PTR = 45º (Vertically opposite angles)
→ ∠STQ = 45º
By using angle sum property for ΔSTQ, we obtain
→ ∠STQ + ∠SQT + ∠QST = 180º
→ 45º + ∠SQT + 75º = 180º
→ ∠SQT = 180º − 120º
→ ∠SQT = 60º
Hence,
- ∠SQT = 60º
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