In the given figure, if O is the centre of the circle,
then find the measure of ZBAP.
25°
Р
AD
D Q
In the given figure, a circle is touching the side BC
of AARC at
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Hello brother
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Answer
Angle ABC = 25°
So, Angle AOD = 50°
(Angle at centre is equal to double of angle at any other part)
Angle BOA = 180 -- 50 = 130°
Now, we can find Angle BAO which will be 25°
Now, Angle BAP will be
25 + 90 = 180°.
(Angle OAD = 90° Because line passing from centre touching tangent makes 90° Angle with it.)
So, Angle BAP = 65°
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