In the given figure, if OA =5cm, AB =8 cm and OC LAB, find CD.
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Answer:
2cm
Step-by-step explanation:
AB = 8 cm
as OC perpendicular to AB, we know that when a perpendicular is drawn from the center to a cord it bisects the chord
So Now we have AC = 4 cm
Using Pythagoras theorem in triangle AOC find the the length of OC
OA² = OC² + AC²
5² = OC² + 4²
5² - 4² = OC²
√25-16 = OC
√9 = OC
3 = 0C
Now OA and OD re the radii of the same circle hence equal
AO = OD
And OD = OC + CD
AO = OD = OC + CD
5 = 3 + CD
5 - 3 = CD
2 = CD
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