Question

In the given figure if OAB = 50°, <ACB = _________-
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Answer 1

Answer:

OA= OB ( radii of same circle)

therefore, <OAB = OBA. = 50°

In triangle, OAB

<OAB + <OBA + <AOB = 180°

50+50+<AOB= 180

<AOB = 180-100

<AOB = 80°

We know that The angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle.

therefore, <AOB=2<ACB

<ACB = 1/2<AOB

= 1/2×80

<ACB = 40°

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