Question

In the given figure if PQ is perpendicular to PS, PQ is parallel to SR, angle SQR= 38° and angle QRT = 75° then find the values of x and y​

Answer 1

Answer:

Answer

Given, PQ⊥PS,PQ∥SR,∠SQR=28

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,∠QRT=65

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According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

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=65

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⇒x=37

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Also ∠QSR=x

⇒∠QSR=37

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Also ∠QRS+∠QRT=180

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(Linear pair)

⇒∠QRS+65

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=180

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⇒∠QRS=115

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Now, ∠P+∠Q+∠R+∠S=360

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(Sum of the angles in a quadrilateral.)

⇒90

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+65

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+115

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+∠S=360

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⇒270

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+y+∠QSR=360

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⇒270

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+y+37

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=360

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⇒307

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+y=360

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⇒y=53

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Step-by-step explanation:

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