IN THE GIVEN FIGURE IF PQ = PR PROVE THAT QT = TR I.E. QR IS BISECTED AT
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Step-by-step explanation:
Given,
PQ = PR
In ∆ PQR , altitude PT is drawn.
Now ,
In ∆PTQ and ∆PTR,
Angle PTQ = Angle PTR = 90°
PT= PT { common side }
PQ = PR { given}
∆ PTQ congruent∆PTR ( By RHS rule)
=> QT = TR
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