In the given figure, if PQ || RS, then find the value of x. Q P 72° T 4x + 20° 48° S R
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Step-by-step explanation:
In triangle QSR we have
angle QRT = angle RSQ+ angle SQR ...(Exterior angle of
triangle is equal t sum of interior opposite angles)
Rightarrow65^ = angle RSQ + 28 deg
Rightarrow angle RSQ = 65 deg - 28 deg
Rightarrow angle RSQ = 37 deg
We have y + RSQ = 90° ....(Given)
3y + 37 deg = 90 deg
Rightarrow y = 90 deg - 37 deg = 53 deg
In triangle PQS we have
x deg + y deg + angle P=180^ ....(Angle sum property)
/ x + 53 deg + 90 deg = 180 deg
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