In the given figure, if PQ = ST, QU = TR
PQI QT and ST I TQ, then prove that
PR = SU.
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In △s PQR and △ STU
PQ I QT (sides are parallel)
< PQR= < STU ( each 90° )
PQ=ST(Given)
Thus, △PQR≅△STU ( RHS )
Hence, SR = TQ (By CPCT)
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