Question

In the given figure ,if PR=24cm and OP=25cm,then the radius of circle is
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Answer 1

∆OPR is a Right - angled triangle

So, By Pythagoras Therom

→ h² = p² + b²

→ (OP)² = (PR)² + (0R)²

→ (25)² = (24)² + (OR)²

→ (OR)² = 625 - 576

→ (OR) = √49

So, OR = 7 cm

And here, OR is the radius

Hence, Radius of circle ; r = 7 cm

Hope it helps.

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