Question

In the given figure, if QOP is a diameter of the
circle and -
1-

4 PMR RNQ  , then the measure of
ROQ is

Answer 1

Answer:

r=diameter/2

R=0.5

QOP=diameter= Angeles=180

Answer 2

Answer:

(3) 36°

Step-by-step explanation:

given

PMR = 1/4 RNQ

To find

angle ROQ =?

since QOP is a diameter of the  circle

means angle poq = 180

PMR+RNQ =180 --------}Semicircle

PMR+4 RNQ=180

180/5=36

RNQ= 4[36]=144

PMR=36  

or  

180-144[RNQ]=36