Question

In the given figure, if seg PR ≌ seg PQ, show that seg PS > seg

PQ.​

Answer 1

Answer:

sorry want free points

Answer 2

In $\triangle PRS,\angle PRS$ is an obtuse angle.

Since, a triangle can have maximum 1 obtuse angle.

Hence,$\angle PRS$ is the greatest angle.

$\therefore$the side opposite to $\angle PRS$ i.e. PS is the longest side.

Now,Seg PS > Seg PR > Seg RS

$\therefore seg\:PS > seg\:PQ\\\:\:\:\: \:\:\because\:segPR≅ seg\:PQ$