Question

in the given figure.if sin A = 8/13 , then find AB​

answer :104/√105

Answer 1

Answer:

HOPE YOU UNDERSTAND!!!

Answer 2

The given question is in the given figure. if sin A = 8/13, then find AB

We have to find the value of AB.

From the data given in the figure

${ab}^{2} = {13x}^{2} - {8x}^{2}$

The above-given expression is the formula for a value p.

${p}^{2} = 105 {x}^{2} \\ p = \sqrt{{105} {x}^{2} } \\ p = \sqrt{105} x$

As it is given that

$\sqrt{105} x = 8$

Therefore, the value of AB will be

$\frac{13 \times 8}{ \sqrt{105} } = \frac{104}{ \sqrt{105} }$

The value of x can also be obtained by another method.

Another method is

$105 {x}^{2} = {8}^{2}$

The number multiplying on the left side changes into the division on the right side.

so, the value will become

${x}^{2} = \frac{ {8}^{2} }{105}$

Taking, the square root on both sides we get the value as

$x = \frac{8}{ \sqrt{105} }$

By using this x value, the value of AB is found to be

$\frac{104}{ \sqrt{105} }$

Therefore, the final answer to the given question is found to be

$\frac{104}{ \sqrt{105} }$

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