in the given figure, if sio 0 = cos (38 - 30°), where 8 and 39 - 30° are acute
angles, then find the value of 0.
What should be the length of the rope of the kite sail in order to pull the ship at
the angle 8 (calculated above) and be at a vertical height of 200 m?
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Answer:
Step-by-step explanation:sin(30)=cos[ 3(30) -30 ]
sin(30)=cos( 90- 30)
sin (30) = sin (30)
therefore, theta = 30
2- In triangle ABC,
Sin(30)=P/H
1/2 =200/H
H= 400
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