in the given figure if the line segment in AB is parallel to another line segment RS and the O is the midpoint of AC then show that triangle ABC is congruent to triangle as O is also the midpoint of the BR
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Step-by-step explanation:
Given: AB is parallel to another line segment CD.
O is the midpoint OF AD
In ΔAOB and ΔDOC
∠AOB=∠COD ...(Vertically opposite angle )
∠BAO=∠CDO ...(Given AB parallel to DC and AD meet both lines so alternate angles are equal)
AO=OD ....(O is the midpoint of AD )
ΔAOB≅ΔDOC ...ASA test
So, BO=CO
Then, O is the midpoint of BC
hope it's helpful for you... all the best....
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