In the given figure, if TU ∥ SR and TR ∥ SV, then find ∠a and ∠b.
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TR II SV
With TA as transversal, <RTA= <TAV= 90° [opp. int. <]
In triangle VAU, <VUT= <UVA+<UAV [ext. < property of triangles]
<a= 25°+90°
<a= 115°
TU II SR
With TR as transversal, <ATR=<TRP=90° [opp. int. <]
<PRQ= 180°-90°= 90°
<RPQ+<PRQ+<RQP= 180° [< sum property of triangles]
<b + 140°= 180°
<b= 180°-140°
<b= 40°
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