In the given figure, if two chords PQ and RS of a circle with centre O intersect each other at M such that
PM = MS, then prove that MR = MQ.
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Given : two chords PQ and RS of a circle with centre O intersect each other at M such that PM = MS
To Find : prove that MR = MQ.
Solution:
Join PR and SQ
m∠QSR = m∠QPR Angle by same arc in same arc segment
=> m∠QSM = m∠MPR
Compare ΔPMR and ΔSMQ
PM = SM given
m∠SMQ = m∠PMR (Vertically opposite angles)
m∠QSM = m∠MPR
ΔPMR ≅ ΔSMQ ( ASA)
∴ MR = MQ ( CPCT)
QED
Hence proved
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