Question

In the given figure if velocity of wave is 320 m/s.
Find the time period of the wave.
(A) 1.25 x 10 ^-3second
(B) 0.0625 second
(C) 0.125 second
(D) 6.25 x 10^-3 second

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Answer 1

Let f = frequency

Time period (T) = \frac{1}{f}

1 oscillation = AC = 20cm*2 = 40cm

$f = \frac{320m/s}{0.4m}$

f = 800/(1s)

$T = \frac{1}{800}s = 1.25\cdot10^{-3}s$

∴ (A) $1.25\cdot10^{-3}s$

Answer 2

As per the data given in the above question.

we have to find the time period.

Given,

wavelength , λ= 20 cm

velocity,v = 320 m/s

Solution:

• A wavelength can be calculated by dividing the velocity of a wave by its frequency. This is often expressed as the equation seen here.

$λ \: = \frac{v}{f}$λ represents wavelength, expressed in meters. The v is wave velocity, calculated as meters per second (mps). And the f stands for frequency, which is measured in hertz (Hz).

• The oscillation process in an extended medium is called an oscillating wave.

$Ac= (20)² cm$

$AC= 400 \: {cm}^{2}$

$Ac= \: \frac{400}{10000} {m}^{2}$

$AC or λ =0.04 m²$

Now from the above formula,

$λ = \frac{v}{f} \: or \: f = \frac{v}{λ}$

$f= \: \frac{320}{0.04}$

$f=8000 \: Hz$

The time period ,

$T= \frac{1}{f}$

$T= \: \frac{1}{8000}$

$T=0.000125 \: sec$

$T=1.25 \times {10}^{ - 3} sec$

Hence ,

option (A) is correct .

Project code #SPJ2