In the given figure, if y, then 3 4 5 calculate the values of x, y and z.
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Given x:y:z=5:4:6 and XOY is a straight line.
Let x=5t;y=4t;z=6t
5t+4t+6t=180
0
15t=180
0
t=12
0
So,
x=5×12
0
=60
0
;
y=4×12
0
=48
0
;
z=6×12
0
=72
0
hope it will help you
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