Question

In the given figure, if ZBAC = 25%, then BOC is equal to

Answer 1

Answer:

In △ABC, AB=AC

Thus, ∠BAC=∠BCA ....(Isosceles triangle property).

Also, ∠BDC=∠BAC=25

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....(Angles in same segment).

In △BDC,

by angle sum property, the sum of angles =180

o

⟹ ∠CBD+∠BCA+∠ACD+∠BDC=180

⟹ ∠ACD=180−75=105

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.

Now, in cyclic quadrilateral ACDE,

∠ACD+∠AED=180 ....(Opposite angles of cyclic quadrilateral)

⟹ ∠AED=180−105

⟹ ∠AED=75

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