Question

In the given figure,
in A ABC, A-P-B and A-Q-C
seg PQ || seg BC.
seg PC and seg QB are drawn.

Prove that, AP/PB=AQ/QC


Write the proof.​

Answer 1

Step-by-step explanation:

Since P and Q are midpoints, according to Midpoint

Theorem :

PQ||BC and PQ = 1/2 BC

Let AR be the median from vertex A on BC. It will pass

through point G, which is also the centroid of the

triangle ABC and also bisects PQ at point 0.

We know Centroid divides AR in the ratio 2:1

And it can be proved that AO:OC = 3:1

Let ARm

Then LOG = 1/4 x 2/3 x m

Now, in an equilateral triangle ABC, the medians and

altitudes are same.

Area = 1/2 x Base x Altitude

Ar PQG = 1/2 x (1/2 x BC) (1/4 x 2/3 x m)

Ar ABC = 1/2 x BC x m

Ar PQG/Ar ABC = 1/12

Answer 2

Answer:

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